(2x^2)/3-2x^2=-12x

Solution for (2x^2)/3-2x^2=-12x equation:

(2x^2)/3-2x^2=-12x

We move all terms to the left:

(2x^2)/3-2x^2-(-12x)=0

We get rid of parentheses

-2x^2+2x^2/3+12x=0

We multiply all the terms by the denominator


2x^2-2x^2*3+12x*3=0

Wy multiply elements

2x^2-6x^2+36x=0

We add all the numbers together, and all the variables

-4x^2+36x=0

a = -4; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-4)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-4}=\frac{-72}{-8}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-4}=\frac{0}{-8}
=0
$